16-2800/x^2=0

Solution for 16-2800/x^2=0 equation:

16-2800/x^2=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


16*x^2-2800=0

We add all the numbers together, and all the variables

16x^2-2800=0

a = 16; b = 0; c = -2800;
Δ = b2-4ac
Δ = 02-4·16·(-2800)
Δ = 179200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{179200}=\sqrt{25600*7}=\sqrt{25600}*\sqrt{7}=160\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160\sqrt{7}}{2*16}=\frac{0-160\sqrt{7}}{32}
=-\frac{160\sqrt{7}}{32}
=-5\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160\sqrt{7}}{2*16}=\frac{0+160\sqrt{7}}{32}
=\frac{160\sqrt{7}}{32}
=5\sqrt{7}
$